John O'Shaughnessy
2005-02-05 22:05:18 UTC
I'm trying to determine how much memory is on the LG VX6100 for the
documentation. Below is the protocol log entries for the query and the
response. If '59 0c' is the request, I'd assume that '00 c0 50 cc 00' is
the response.
Converting those hex digits to decimal yields: 0 192 80 204 0
Are we looking at 19Mb? It doesn't seem to round to any multiple of 1024.
Thanks for any interpretation assistance.
John
15:45:08.403 LG-VX6100: brew request Data - 2 bytes
<#! p_brew.memoryconfigrequest !#>
00000000 59 0c Y.
15:45:08.403 LG-VX6100: brew response Data - 7 bytes
<#! p_brew.memoryconfigresponse !#>
00000000 59 0c 00 c0 50 cc 00 Y...P..
documentation. Below is the protocol log entries for the query and the
response. If '59 0c' is the request, I'd assume that '00 c0 50 cc 00' is
the response.
Converting those hex digits to decimal yields: 0 192 80 204 0
Are we looking at 19Mb? It doesn't seem to round to any multiple of 1024.
Thanks for any interpretation assistance.
John
15:45:08.403 LG-VX6100: brew request Data - 2 bytes
<#! p_brew.memoryconfigrequest !#>
00000000 59 0c Y.
15:45:08.403 LG-VX6100: brew response Data - 7 bytes
<#! p_brew.memoryconfigresponse !#>
00000000 59 0c 00 c0 50 cc 00 Y...P..